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Properties of Atoms. Spectra.

Problem 6.99

Find the binding energy of a valence electron in the ground state of a Li atom if the wavelength of the first line of the sharp series is known to be equal to λ1=813nm\lambda_{1}=813 \mathrm{nm} and the short-wave cut-off wavelength of that series to λ2=350nm\lambda_{2}=350 \mathrm{nm}.

Reveal Answer
Eb=ℏR/(Rλ1λ2/2πcΔλ−1)2=5.3eVE_{b}=\hbar R /\left(\sqrt{R \lambda_{1} \lambda_{2} / 2 \pi c \Delta \lambda}-1\right)^{2}=5.3 \mathrm{eV}
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