Problem 6.98

6.98, Find the Rydberg correction for the $3 P$ term of a $\mathrm{Na}$ atom whose first excitation potential is $2.10 \mathrm{~V}$ and whose valence electron in the normal $3 S$ state has the binding energy $5.14 \mathrm{eV}$ .

\alpha=\sqrt{\hbar R /\left(E_{0}-e \varphi_{1}\right)}-3=-0.88

Properties of Atoms. Spectra.