Problem 6.16

Find the effective cross section of a uranium nucleus corresponding to the scattering of alpha particles with kinetic energy \(T=1.5 \mathrm{MeV}\) through the angles exceeding \(\theta_{0}=60^{\circ}\)

Reveal Answer

\Delta \sigma=\pi\left(Z e^{2} / T\right)^{2} \cot ^{2}\left(\theta_{0} / 2\right)=0.73 \mathrm{~kb}

Scattering of Particles. Rutherford-Bohr Atom