All Problems

Optics of Moving Sources

Problem 5.236

A source emitting electromagnetic signals with proper frequency ω0=3.01010 s1\omega_{0}=3.0 \cdot 10^{10} \mathrm{~s}^{-1} moves at a constant velocity vv =0.80c=0.80 c along a straight line separated from a stationary observer PP by a distance ll (Fig. 5.37 ). Find the frequency of the signals perceived by the observer at the moment when (a) the source is at the point OO; (b) the observer sees it at the point OO.

Reveal Answer
5.236.( a) ω=ω0/1β2=5.01010 s1;(b)ω=ω01β2==1.81010 s1.Here β=v/c.\begin{aligned} & 5.236 .\left(\right.\text { a) } \omega=\omega_{0} / \sqrt{1-\beta^{2}}=5.0 \cdot 10^{10} \mathrm{~s}^{-1} ;(b) \omega=\omega_{0} \sqrt{1-\beta^{2}}=\\ =& 1.8 \cdot 10^{10} \mathrm{~s}^{-1} . \text {Here } \beta=v / c . \end{aligned}