All Problems

Polarization of Light

Problem 5.189

Using the tables of the Appendix, calculate the difference of refractive indices of quartz for light of wavelength \(\lambda=589.5 \mathrm{nm}\) with right-hand and left-hand circular polarizations.

Reveal Answer
Δn=αλ/π=0.71⋅10−4,where α is the rotational constant \Delta n=\alpha \lambda / \pi=0.71 \cdot 10^{-4}, \text {where } \alpha \text { is the rotational constant }
Prev
Next