All Problems

Mechanical Oscillations

Problem 4.66

A coil of inductance LL connects the upper ends of two vertical copper bars separated by a distance ll. A horizontal conducting connector of mass mm starts falling with zero initial velocity along the bars without losing contact with them. The whole system is located in a uniform magnetic field with induction BB perpendicular to the plane of the bars. Find the law of motion x(t)x(t) of the connector.

Reveal Answer
x=(1cosωt)g/ω2, where ω=lB/mLx=(1-\cos \omega t) g / \omega^{2}, \text { where } \omega=l B / \sqrt{m L}