All Problems

Mechanical Oscillations

Problem 4.39

A body of mass m=0.50 kgm=0.50 \mathrm{~kg} is suspended from a rubber cord with elasticity coefficient k=50 N/mk=50 \mathrm{~N} / \mathrm{m}. Find the maximum distance over which the body can be pulled down for the body's oscillations to remain harmonic. What is the energy of oscillation in this case?

Reveal Answer
Δhmax⁡=mg/k=10 cm,E=m2g2/2k=4.8 mJ\Delta h_{\max }=m g / k=10 \mathrm{~cm}, E=m^{2} g^{2} / 2 k=4.8 \mathrm{~mJ}
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