Problem 4.121

A circuit consisting of a capacitor and an active resistance $R=110 \Omega$ connected in series is fed an alternating voltage with amplitude $V_{m}=110 \mathrm{~V}$. In this case the amplitude of steady-state current is equal to $I_{m}=0.50 \mathrm{~A}$. Find the phase difference between the current and the voltage fed.