All Problems Electric Oscillations
Problem 4.121
A circuit consisting of a capacitor and an active resistance \(R=110 \Omega\) connected in series is fed an alternating voltage with amplitude \(V_{m}=110 \mathrm{~V}\). In this case the amplitude of steady-state current is equal to \(I_{m}=0.50 \mathrm{~A}\). Find the phase difference between the current and the voltage fed.
4.121. The current is ahead of the voltage by the phase angle \(\varphi=60^{\circ},\) defined by the equation \(\tan \varphi=\sqrt{\left(V_{m} / R I_{m}\right)^{2}-1}\)