Problem 3.181

Find the magnitude and direction of the current flowing through the resistance $R$ in the circuit shown in Fig. 3.44 if the emf's of the sources are equal to $\mathscr{E}_ {1}=1.5 \mathrm{~V}$ and $\mathscr{E}_ {2}=3.7 \mathrm{~V}$ and the resistances are equal to $R_{1}=10 \Omega, R_{2}=20 \Omega, R=5.0 \Omega$ . The internal resistances of the sources are negligible.

I=\left(R_{1} \mathscr{E}_{2}-R_{2} \mathscr{E}_{1}\right) /\left(R R_{1}+R_{1} R_{2}+R_{2} R\right)=0.02 \mathrm{~A}, \text { the current is directed from the left to the right (see Fig. 3.44).}

Electric Current