In the circuit shown in Fig. 3.42 the emf of the source is equal to E=5.0 V\mathscr{E}=5.0 \mathrm{~V}E=5.0 V and the resistances are equal to Ry=4.0ΩR_{\mathrm{y}}=4.0 \OmegaRy=4.0Ω and R2=6.0ΩR_{2}=6.0 \OmegaR2=6.0Ω. The internal resistance of the source equals RRR =0.10Ω=0.10 \Omega=0.10Ω. Find the currents flowing through the resistances R1R_{1}R1 and R2R_{2}R2