All Problems

Electric Current

Problem 3.178

In the circuit shown in Fig. 3.42 the emf of the source is equal to E=5.0 V\mathscr{E}=5.0 \mathrm{~V} and the resistances are equal to Ry=4.0ΩR_{\mathrm{y}}=4.0 \Omega and R2=6.0ΩR_{2}=6.0 \Omega. The internal resistance of the source equals RR =0.10Ω=0.10 \Omega. Find the currents flowing through the resistances R1R_{1} and R2R_{2}

Reveal Answer
I1=ER2/(RR1+R1R2+R2R)=1.2 A,I2=I1R1/R2=0.9AI_{1}=\mathscr{E} R_{2} /\left(R R_{1}+R_{1} R_{2}+R_{2} R\right)=1.2 \mathrm{~A}, I_{2}=I_{1} R_{1} / R_{2}=0.9 A