All Problems

Electric Current

Problem 3.176

sources of current with different emf's are connected as shown in Fig. 3.40. The emf's of the sources are proportional to their internal resistances, i.e. E=αR,\mathscr{E}=\alpha R, where α\alpha is an assigned constant. The lead wire resistance is negligible. Find: (a) the current in the circuit; (b) the potential difference between points AA and BB dividing the circuit in nn and NnN-n links.

Reveal Answer
(a) I=αI=\alpha; (b) φAφB=0\varphi_{A}-\varphi_{B}=0