All Problems

Electric Current

Problem 3.171

A capacitor filled with dielectric of permittivity \(\varepsilon=2.1\) loses half the charge acquired during a time interval \(\tau=3.0 \mathrm{~min}\). Assuming the charge to leak only through the dielectric filler, calculate its resistivity.

Reveal Answer
ρ=τ/ε0εln2=1.41013Ωm\rho=\tau / \varepsilon_{0} \varepsilon \ln 2=1.4 \cdot 10^{13} \Omega \cdot \mathrm{m}