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Wave Properties of particles. Schrodinger Equation.

Problem 6.91

Find the energy of an electron of a hydrogen atom in a stationary state for which the wave function takes the form ψ(r)=\psi(r)= =A(1+ar)e−αr,=A(1+a r) \mathrm{e}^{-\alpha r}, where A,a,A, a, and α\alpha are constants.

Reveal Answer
E=−me4/8ℏ2, i.e. the level with principal quantum number n = 2E=-m e^{4} / 8 \hbar^{2}, \text { i.e. the level with principal quantum number n = 2}
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