Problem 6.91

Find the energy of an electron of a hydrogen atom in a stationary state for which the wave function takes the form \(\psi(r)=\) \(=A(1+a r) \mathrm{e}^{-\alpha r},\) where \(A, a,\) and \(\alpha\) are constants.

E=-m e^{4} / 8 \hbar^{2}, \text { i.e. the level with principal quantum number n = 2}

Wave Properties of particles. Schrodinger Equation.