All Problems

Scattering of Particles. Rutherford-Bohr Atom

Problem 6.38

The binding energy of an electron in the ground state of He\mathrm{He} atom is equal to E0=24.6eVE_{0}=24.6 \mathrm{eV}. Find the energy required to remove both electrons from the atom.

Reveal Answer
E=E0+4R=79eVE=E_{0}+4 \hbar R=79 \mathrm{eV}