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Elementary Particles

Problem 6.301

A neutral pion disintegrated during its flight into two gamma quanta with equal energies. The angle of divergence of gamma quanta is Θ=60∘.\Theta=60^{\circ} . Find the kinetic energy of the pion and of each gamma quantum.

Reveal Answer
 6.301*. Tπ=mπ[cosec⁡(Θ/2)−1],Eγ=mπ/2sin⁡(Θ/2). For Θ=60∘ the energy Tπ=Eγ=mπ\begin{aligned} &\text { 6.301*. } T_{\pi}=m_{\pi}[\operatorname{cosec}(\Theta / 2)-1], E_{\gamma}=m_{\pi} / 2 \sin (\Theta / 2) . \text { For }\\ &\Theta=60^{\circ} \text { the energy } T_{\pi}=E_{\gamma}=m_{\pi} \end{aligned}
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