An alpha particle with kinetic energy T=5.3MeVT=5.3 \mathrm{MeV}T=5.3MeV initiates a nuclear reaction Be9(α,n)C12\mathrm{Be}^{9}(\alpha, n) \mathrm{C}^{12}Be9(α,n)C12 with energy yield Q=Q=Q= =+5.7MeV=+5.7 \mathrm{MeV}=+5.7MeV. Find the kinetic energy of the neutron outgoing at right angles to the motion direction of the alpha-particle.