Taking the values of atomic masses from the tables, caiculate the energy per nucleon which is liberated in the nuclear reaction Li6+H2→2He4.\mathrm{Li}^{6}+\mathrm{H}^{2} \rightarrow 2 \mathrm{He}^{4} .Li6+H2→2He4. Compare the obtained magnitude with the energy per nucleon liberated in the fission of U235\mathrm{U}^{235}U235 nucleus.