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Nuclear Reactions

Problem 6.249

An alpha-particle with kinetic energy Tα=7.0MeVT_{\alpha}=7.0 \mathrm{MeV} is scattered elastically by an initially stationary Li6\mathrm{Li}^{6} nucleus. Find the kinetic energy of the recoil nucleus if the angle of divergence of the two particles is Θ=60∘\Theta=60^{\circ}

Reveal Answer
 6.249. T=Tα/[1+(M−m)2/4mMcos⁡2Θ]=6.0MeV, where  \text { 6.249. } T=T_{\alpha} /\left[1+(M-m)^{2} / 4 m M \cos ^{2} \Theta\right]=6.0 \mathrm{MeV}, \text { where } mm and MM are the masses of an alpha particle and a lithium nucleus.
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