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Radioactivity

Problem 6.228

A P32P^{32} radionuclide with half-life T=14.3T=14.3 days is produced in a reactor at a constant rate q=2.7⋅109q=2.7 \cdot 10^{9} nuclei per second. How soon after the beginning of production of that radionuclide will its activity be equal to A=1.0⋅109dis/s?A=1.0 \cdot 10^{9} \mathrm{dis} / \mathrm{s} ?

Reveal Answer
t=−(T/ln⁡2)ln⁡(1−A/q)=9.5 days. t=-(T / \ln 2) \ln (1-A / q)=9.5 \text { days. }
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