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Molecules and Crystals

Problem 6.211

In Hall effect measurements a plate of width \(h=10 \mathrm{~mm}\) and length \(l=50 \mathrm{~mm}\) made of \(p\) -type semiconductor was placed in a magnetic field with induction \(B=5.0 \mathrm{kG}\). A potential difference \(V=10 \mathrm{~V}\) was applied across the edges of the plate. In this case the Hall field is \(V_{H}=50 \mathrm{mV}\) and resistivity \(\rho=2.5 \Omega \cdot \mathrm{cm}\) Find the concentration of holes and hole mobility.

Reveal Answer
 6.211. n=hBV/elρVH=5⋅1015 cm−3,u0=lVH/hBV==0.05 m2/(V⋅s)\begin{aligned} &\text { 6.211. } n=h B V / e l \rho V_{H}=5 \cdot 10^{15} \mathrm{~cm}^{-3}, u_{0}=l V_{\mathrm{H}} / h B V=\\ &=0.05 \mathrm{~m}^{2} /(\mathrm{V} \cdot \mathrm{s}) \end{aligned}
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