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Molecules and Crystals

Problem 6.186

Calculate the Debye temperature for iron in which the propagation velocities of longitudinal and transverse vibrations are equal to 5.85 and 3.23 km/s3.23 \mathrm{~km} / \mathrm{s} respectively.

Reveal Answer
Θ=(ℏ/k)18π2n0/(v∥−3+2v⊥−3)3=470 K, where n0 is the concentration of the atoms \Theta=(\hbar / k) \sqrt[3]{18 \pi^{2} n_{0} /\left(v_{\|}^{-3}+2 v_{\perp}^{-3}\right)}=470 \mathrm{~K}, \text { where } n_{0} \text { is the concentration of the atoms }
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