All Problems

Properties of Atoms. Spectra.

Problem 6.141

Find the binding energy of an LL electron in titanium if the wavelength difference between the first line of the KK series and its short-wave cut-off is Δλ=26pm\Delta \lambda=26 \mathrm{pm}

Reveal Answer
EL=ℏω(2πc/ωΔλ−1)≈0.5keV, where ω=3/4R(Z−1)2E_{L}=\hbar \omega(2 \pi c / \omega \Delta \lambda-1) \approx 0.5 \mathrm{keV}, \quad \text { where } \quad \omega=3 / 4 R(Z-1)^{2}
Prev
Next