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Properties of Atoms. Spectra.

Problem 6.141

Find the binding energy of an \(L\) electron in titanium if the wavelength difference between the first line of the \(K\) series and its short-wave cut-off is \(\Delta \lambda=26 \mathrm{pm}\)

Reveal Answer
EL=ℏω(2πc/ωΔλ−1)≈0.5keV, where ω=3/4R(Z−1)2E_{L}=\hbar \omega(2 \pi c / \omega \Delta \lambda-1) \approx 0.5 \mathrm{keV}, \quad \text { where } \quad \omega=3 / 4 R(Z-1)^{2}
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