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Scattering of Particles. Rutherford-Bohr Atom

Problem 6.14

A narrow beam of alpha particles with kinetic energy TT =1.1⋅1019=1.1 \cdot 10^{19} nuclei /cm2/ \mathrm{cm}^{2}. Find the fraction of alpha particles scattered through the angles θ<θ0=20∘\theta<\theta_{0}=20^{\circ}

Reveal Answer
ΔN/N=1−πnZ2e4/T2tan⁡2(θ0/2)=0.6\Delta N / N=1-\pi n Z^{2} e^{4} / T^{2} \tan ^{2}\left(\theta_{0} / 2\right)=0.6
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