All Problems

Photometry and Geometrical Optics

Problem 5.38

A thin converging lens with aperture ratio D:f=1:3.5D: f=1: 3.5 ( DD is the lens diameter, ff is its focal length) provides the image of a sufficiently distant object on a photographic plate. The object luminance is L=260 cd/m2.L=260 \mathrm{~cd} / \mathrm{m}^{2} . The losses of light in the lens amount to α=0.10.\alpha=0.10 . Find the illuminance of the image.

Reveal Answer
E=(1α)πLD2/4f2=15 lxE=(1-\alpha) \pi L D^{2} / 4 f^{2}=15 \mathrm{~lx}