Problem 5.290

A photon with energy $\hbar \omega=0.15 \mathrm{MeV}$ is scattered by a stationary free electron changing its wavelength by $\Delta \lambda=3.0 \mathrm{pm}$ . Find the angle at which the Compton electron moves.

Reveal Answer

\tan \varphi=\frac{\sqrt{4 \pi \hbar / m c \Delta \lambda-1}}{1+\hbar \omega / m c^{2}}, \varphi=31^{\circ}

Thermal Radiation. Quantum Nature of Light.