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Optics of Moving Sources

Problem 5.245

Find the kinetic energy of electrons emitting light in a medium with refractive index n=1.50n=1.50 at an angle θ=30∘\theta=30^{\circ} to their propagation direction.

Reveal Answer
T=(ncos⁡θn2cos⁡2θ−1−1)mc2=0.23MeVT=\left(\frac{n \cos \theta}{\sqrt{n^{2} \cos ^{2} \theta-1}}-1\right) m c^{2}=0.23 \mathrm{MeV}
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