All Problems

Optics of Moving Sources

Problem 5.245

Find the kinetic energy of electrons emitting light in a medium with refractive index \(n=1.50\) at an angle \(\theta=30^{\circ}\) to their propagation direction.

Reveal Answer
T=(ncosθn2cos2θ11)mc2=0.23MeVT=\left(\frac{n \cos \theta}{\sqrt{n^{2} \cos ^{2} \theta-1}}-1\right) m c^{2}=0.23 \mathrm{MeV}