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Dispersion and Absorption of Light

Problem 5.210

The refractive index of carbon dioxide at the wavelengths \(509,534,\) and \(589 \mathrm{nm}\) is equal to \(1.647,1.640,\) and 1.630 respectively. Calculate the phase and group velocities of light in the vicinity of \(\lambda=534 \mathrm{nm}\)

Reveal Answer
5.210.v=c/n=1.83⋅108 m/s,u=[1+(λ/n)(dn/dλ)]c/n==1.70⋅108 m/s.\begin{aligned} & 5.210 . v=c / n=1.83 \cdot 10^{8} \quad \mathrm{~m} / \mathrm{s}, \quad u=[1+(\lambda / n)(d n / d \lambda)] c / n=\\ =& 1.70 \cdot 10^{8} \mathrm{~m} / \mathrm{s} . \end{aligned}
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