All Problems

Polarization of Light

Problem 5.194

A Kerr cell is positioned between two crossed Nicol prisms so that the direction of electric field E\mathbf{E} in the capacitor forms an angle of 4545^{\circ} with the principal directions of the prisms. The capacitor has the length l=10 cml=10 \mathrm{~cm} and is filled up with nitrobenzene. Light of wavelength λ=0.50μm\lambda=0.50 \mu \mathrm{m} passes through the system. Taking into account that in this case the Kerr constant is equal to BB =2.21010 cm/V2,=2.2 \cdot 10^{-10} \mathrm{~cm} / \mathrm{V}^{2}, find: (a) the minimum strength of electric field EE in the capacitor at which the intensity of light that passes through this system is independent of rotation of the rear prism; (b) how many times per second light will be interrupted when a sinusoidal voltage of frequency v=10MHzv=10 \mathrm{MHz} and strength amplitude Em=50kV/cmE_{m}=50 \mathrm{kV} / \mathrm{cm} is applied to the capacitor.

Note. The Kerr constant is the coefficient Bˉ\bar{B} in the equation nen_{e}- n0=BλE2-n_{0}=B \lambda E^{2}

Reveal Answer
(a) Emin=1/4Bl=10.6kV/cmE_{\min }=1 / \sqrt{4 B l}=10.6 \mathrm{kV} / \mathrm{cm} (b) 2.21082.2 \cdot 10^{8} interruptions per second