All Problems

Photometry and Geometrical Optics

Problem 5.18

A man standing on the edge of a swimming pool looks at a stone lying on the bottom. The depth of the swimming pool is equal to hh. At what distance from the surface of water is the image of the stone formed if the line of vision makes an angle θ\theta with the normal to the surface?

Reveal Answer
h′=(hn2cos⁡3θ)/(n2−sin⁡2θ)3/2h^{\prime}=\left(h n^{2} \cos ^{3} \theta\right) /\left(n^{2}-\sin ^{2} \theta\right)^{3 / 2}
Prev
Next