All Problems

Polarization of Light

Problem 5.165

Two parallel plane-polarized beams of light of equal intensity whose oscillation planes N1N_{1} and N2N_{2} form a small angle φ\varphi between them (Fig. 5.30) fall on a Nicol prism. To equalize the intensities of the beams emerging behind the prism, its principal direction NN must be aligned along the bisecting line AA or BB. Find the value of the angle φ\varphi at which the rotation of the Nicol prism through a small angle δφφ\delta \varphi \ll \varphi from the position AA results in the fractional change of intensities of the beams ΔI/I\Delta I / I by the value η=100\eta=100 times exceeding that resulting due to rotation through the same angle from the position BB.

Reveal Answer
5.165.5.165 . The relative intensity variations of both beams in the cases AA and BB are (ΔI/I)A=4cot(φ/2)δφ,(ΔI/I)B=4tan(φ/2)δφ (\Delta I / I)_{A}=4 \cot (\varphi / 2) \cdot \delta \varphi, \quad(\Delta I / I)_{B}=4 \tan (\varphi / 2) \cdot \delta \varphi Hence η=(ΔI/I)A/(ΔI/I)B=cot2(φ/2),φ=11.5 \eta=(\Delta I / I)_{A} /(\Delta I / I)_{B}=\cot ^{2}(\varphi / 2), \varphi=11.5^{\circ}