All Problems

Polarization of Light

Problem 5.159

A beam of plane-polarized light falls on a polarizer which rotates about the axis of the ray with angular velocity \(\omega=21 \mathrm{rad} / \mathrm{s}\). Find the energy of light passing through the polarizer per one revolution if the flux of energy of the, incident ray is equal to \(\Phi_{0}\) \(=4.0 \quad \mathrm{~mW}\)

Reveal Answer
E=πΦ0/ω=0.6 mJE=\pi \Phi_{0} / \omega=0.6 \mathrm{~mJ}