All Problems

Polarization of Light

Problem 5.159

A beam of plane-polarized light falls on a polarizer which rotates about the axis of the ray with angular velocity ω=21rad/s\omega=21 \mathrm{rad} / \mathrm{s}. Find the energy of light passing through the polarizer per one revolution if the flux of energy of the, incident ray is equal to Φ0\Phi_{0} =4.0 mW=4.0 \quad \mathrm{~mW}

Reveal Answer
E=πΦ0/ω=0.6 mJE=\pi \Phi_{0} / \omega=0.6 \mathrm{~mJ}