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Diffraction of Light

Problem 5.122

A plane light wave with wavelength λ=0.60μm\lambda=0.60 \mu \mathrm{m} falls normally on the face of a glass wedge with refracting angle Θ=15∘\Theta=15^{\circ}. The opposite face of the wedge is opaque and has a slit of width b=10b=10 \mum parallel to the edge. Find: (a) the angle Δθ\Delta \theta between the direction to the Fraunhofer maximum of zeroth order and that of incident light; (b) the angular width of the Fraunhofer maximum of the zeroth order.

Reveal Answer
5.122. (a) Δθ=arcsin⁡(nsin⁡θ)−θ=7.9∘\Delta \theta=\arcsin (n \sin \theta)-\theta=7.9^{\circ} (b) from the condition b(sin⁡θ1−nsin⁡θ)=±λb\left(\sin \theta_{1}-n \sin \theta\right)=\pm \lambda we obtain Δθ=θ+1−θ−1=\Delta \theta=\theta_{+1}-\theta_{-1}= =7.3∘=7.3^{\circ}
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