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Conductors and Dielectrics in an Electric Field

Problem 3.71

An electric field of strength E=1.0kV/cmE=1.0 \mathrm{kV} / \mathrm{cm} produces polarization in water equivalent to the correct orientation of only one out of NN molecules. Find NN. The electric moment of a water molecule equals p=0.62⋅10−29C⋅mp=0.62 \cdot 10^{-29} \mathrm{C} \cdot \mathrm{m}

Reveal Answer
 3.71. N=n0p(ε−1)ε0E=3⋅103 ,  where n0 is the concentration of molecules. \begin{aligned} &\text { 3.71. } N=\frac{n_{0} p}{(\varepsilon-1) \varepsilon_{0} E}=3 \cdot 10^{3} \text { , }\\ &\text { where } n_{0} \text { is the concentration of molecules. } \end{aligned}
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