All Problems

Motion of Charged Particles in Electric and Magnetic Fields

Problem 3.378

A proton accelerated by a potential difference \(V=500 \mathrm{kV}\) flies through a uniform transverse magnetic field with induction \(B=0.51\) T. The field occupies a region of space \(d=10 \mathrm{~cm}\) in thickness (Fig. 3.99). Find the angle \(\alpha\) through which the proton deviates from the initial direction of its motion.

Reveal Answer
α=arcsin⁡(dBq2mV)=30∘\alpha=\arcsin \left(d B \sqrt{\frac{q}{2 m V}}\right)=30^{\circ}
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