All Problems

Motion of Charged Particles in Electric and Magnetic Fields

Problem 3.372

At the moment \(t=0\) an electron leaves one plate of a parallel-plate capacitor with a negligible velocity. An accelerating voltage, varying as \(V=a t,\) where \(a=100 \mathrm{~V} / \mathrm{s},\) is applied between the plates. The separation between the plates is \(l=5.0 \mathrm{~cm} .\) What is the velocity of the electron at the moment it reaches the opposite plate?

Reveal Answer
v=9/2ale/m3=16 km/sv=\sqrt[3]{9 / 2 a l e / m}=16 \mathrm{~km} / \mathrm{s}
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