All Problems

Motion of Charged Particles in Electric and Magnetic Fields

Problem 3.372

At the moment t=0t=0 an electron leaves one plate of a parallel-plate capacitor with a negligible velocity. An accelerating voltage, varying as V=at,V=a t, where a=100 V/s,a=100 \mathrm{~V} / \mathrm{s}, is applied between the plates. The separation between the plates is l=5.0 cm.l=5.0 \mathrm{~cm} . What is the velocity of the electron at the moment it reaches the opposite plate?

Reveal Answer
v=9/2ale/m3=16 km/sv=\sqrt[3]{9 / 2 a l e / m}=16 \mathrm{~km} / \mathrm{s}