An iron tore supports N=500N=500N=500 turns. Find the magnetic field energy if a current I^=2.0\hat{I}=2.0I^=2.0 A produces a magnetic flux across the tore's cross-section equal to Φ=1.0mWb\Phi=1.0 \mathrm{mWb}Φ=1.0mWb.