A ring of radius \(a=50 \mathrm{~mm}\) made of thin wire of radius \(b=1.0 \mathrm{~mm}\) was located in a uniform magnetic field with induction \(B=0.50 \mathrm{mT}\) so that the ring plane was perpendicular to the vector \(\mathrm{B}\) Then the ring was cooled down to a superconducting state, and the magnetic field was switched off. Find the ring current after that. Note that the inductance of a thin ring along which the surface current flows is equal to \(L=\mu_{0} a\left(\ln \frac{8 a}{b}-2\right)\)