All Problems

Electric Current

Problem 3.160

The gap between the plates of a parallel-plate capacitor is filled with glass of resistivity ρ=100GΩm.\rho=100 \mathrm{G} \Omega \cdot \mathrm{m} . The capacitance of the capacitor equals C=4.0nFC=4.0 \mathrm{nF}. Find the leakage current of the capacitor when a voltage V=2.0kVV=2.0 \mathrm{kV} is applied to it.

Reveal Answer
I=VC/ρεε0=1.5μAI=V C / \rho \varepsilon \varepsilon_{0}=1.5 \mu \mathrm{A}