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Electric Capacitance, Energy of an Electric Field

Problem 3.131

A capacitor of capacitance C1=1.0μFC_{1}=1.0 \mu \mathrm{F} carrying initially a voltage V=300 VV=300 \mathrm{~V} is connected in parallel with an uncharged capacitor of capacitance C2=2.0μFC_{2}=2.0 \mu \mathrm{F}. Find the increment of the electric energy of this system by the moment equilibrium is reached. Explain the result obtained.

Reveal Answer
ΔW=−1/2V2C1C2/(C1+C2)=−0.03 mJ\Delta W=-1 / 2 V^{2} C_{1} C_{2} /\left(C_{1}+C_{2}\right)=-0.03 \mathrm{~mJ}
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