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Electric Capacitance, Energy of an Electric Field
Problem 3.119
Find the charge of each capacitor in the circuit shown in Fig. 3.22.
Reveal Answer
q
=
∣
E
1
−
E
2
∣
C
1
C
2
/
(
C
1
+
C
2
)
q=\left|\mathscr{E}_{1}-\mathscr{E}_{2}\right| C_{1} C_{2} /\left(C_{1}+C_{2}\right)
q
=
∣
E
1
−
E
2
∣
C
1
C
2
/
(
C
1
+
C
2
)
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