Problem 3.107

There is a double-layer cylindrical capacitor whose parameters are shown in Fig. 3.16. The breakdown field strength values for these dielectrics are equal to $E_{1}$ and $E_{2}$ respectively. What is the breakdown voltage of this capacitor if $\varepsilon_{1} R_{1} E_{1}<\varepsilon_{2} R_{2} E_{2} ?$

V=R_{1} E_{1}\left[\ln \left(R_{2} / R_{1}\right)+\left(\varepsilon_{1} / \varepsilon_{2}\right) \ln \left(R_{3} / R_{2}\right)\right]

Electric Capacitance, Energy of an Electric Field