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First law of thermodynamics, heat capacity

Problem 2.57

Find the work performed by one mole of a Van der Waals gas during its isothermal expansion from the volume \(V_{1}\) to \(V_{2}\) at a temperature \(T\).

Reveal Answer
 2.57. A=RTln⁡V2−bV1−b+a(1V2−1V1), where a and b are Van  der Waals constants. \begin{aligned} &\text { 2.57. } A=R T \ln \frac{V_{2}-b}{V_{1}-b}+a\left(\frac{1}{V_{2}}-\frac{1}{V_{1}}\right), \text { where } a \text { and } b \text { are Van }\\ &\text { der Waals constants. } \end{aligned}
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