All Problems

Equation of the gas state processes

Problem 2.5

A vessel of volume \(V=7.5\) l contains a mixture of ideal gases at a temperature \(T=300 \mathrm{~K}: v_{1}=0.10\) mole of oxygen, \(v_{2}=0.20\) mole of nitrogen, and \(v_{3}=0.30\) mole of carbon dioxide. Assuming the gases to be ideal, find: (a) the pressure of the mixture; (b) the mean molar mass \(M\) of the given mixture which enters its equation of state \(p V=(m / M) R T,\) where \(m\) is the mass of the mixture.

Reveal Answer
 (a) p=(v1+v2+v3)RT/V=2.0 atm; ext(b)M=(v1M1+v2M2+v3M3)/(v1+v2+v3)=36.7 g/mol\text { (a) } p=\left(v_{1}+v_{2}+v_{3}\right) R T / V=2.0 \text { atm; } ext { (b) } M=\left(v_{1} M_{1}+v_{2} M_{2}+v_{3} M_{3}\right) /\left(v_{1}+v_{2}+v_{3}\right)=36.7 \mathrm{~g} / \mathrm{mol}
Prev
Next