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First law of thermodynamics, heat capacity

Problem 2.47

One mole of argon is expanded polytropically, the polytropic constant being n=1.50.n=1.50 . In the process, the gas temperature changes by ΔT=−26 K\Delta T=-26 \mathrm{~K}. Find: (a) the amount of heat obtained by the gas; (b) the work performed by the gas.

Reveal Answer
 (a) Q=R(n−γ)ΔT/(n−1)(γ−1)=0.11 kJ;(b)A=−RDeltaT/(n−1)=0.43mathrm kJ\text { (a) } Q=R(n-\gamma) \Delta T /(n-1)(\gamma-1)=0.11 \mathrm{~kJ} ; (b) A=-R Delta T /(n-1)=0.43 mathrm{~kJ}
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