All Problems

First law of thermodynamics, heat capacity

Problem 2.31

As a result of the isobaric heating by ΔT=72 K\Delta T=72 \mathrm{~K} one mole of a certain ideal gas obtains an amount of heat Q=1.60 kJ.Q=1.60 \mathrm{~kJ} . Find the work performed by the gas, the increment of its internal energy, and the value of γ=Cp/C⃗V\gamma=C_{p} / \vec{C}_{V}.

Reveal Answer
\begin{array}{l} \text { 2.31. } A=R \Delta \{T}=0.60 \quad \mathrm{~kJ}, \quad \Delta U=Q-R \Delta T=1.00 \mathrm{~kJ}, \\ \gamma=Q /(Q-R \Delta T)=1.6 \end{array}
Prev
Next