All Problems

Phase Transformations

Problem 2.192

If an additional pressure Δp\Delta p of a saturated vapour over a convex spherical surface of a liquid is considerably less than the vapour pressure over a plane surface, then Δp=(ρv/ρl)2α/r,\Delta p=\left(\rho_{v} / \rho_{l}\right) 2 \alpha / r, where ρv\rho_{v} and ρl\rho_{l} are the densities of the vapour and the liquid, α\alpha is, the surface tension, and rr is the radius of curvature of the surface. Using this formula, find the diameter of water droplets at which the saturated vapour pressure exceeds the vapour pressure over the plane surface by η=1.0%\eta=1.0 \% at a temperature t=27C.t=27^{\circ} \mathrm{C.} The vapour is assumed to be an ideal gas.

Reveal Answer
d4αM/ηρRT=0.2μm, where ρ is the density of waterd \approx 4 \alpha M / \eta \rho R T=0.2 \mu \mathrm{m}, \text { where } \rho \text { is the density of water}