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Phase Transformations

Problem 2.186

A vessel of volume \(V=6.0\) l contains water together with its saturated vapour under a pressure of 40 atm and at a temperature of \(250^{\circ} \mathrm{C}\). The specific volume of the vapour is equal to \(V_{v}^{\prime}=50 \mathrm{l} / \mathrm{kg}\) under these conditions. The total mass of the system water-vapour equals \(m=5.0 \mathrm{~kg} .\) Find the mass and the volume of the vapour.

Reveal Answer
\[ \text { 2.186. } m_{v}=\left(V-m V_{l}^{\prime}\right) /\left(V_{v}^{\prime}-V_{l}^{\prime}\right)=20 \] \(\mathrm{g}, \quad V_{0}=1.0 \mathrm{l}\). Here \(V_{i}^{\prime}\) is the specific volume of water.