All Problems

The Fundamental Equation of Dynamics

Problem 1.69

A bar of mass mm resting on a smooth horizontal plane starts moving due to the force F=mg/3F=m g / 3 of constant magnitude. In the process of its rectilinear motion the angle α\alpha between the direction of this force and the horizontal varies as α=as,\alpha=a s, where aa is a constant, and ss is the distance traversed by the bar from its initial position. Find the velocity of the bar as a function of the angle α\alpha.

Reveal Answer
v=(2g/3a)sinαv=\sqrt{(\overline{2 g / 3 a) \sin \alpha}}