All Problems

The Fundamental Equation of Dynamics

Problem 1.61

Two touching bars 1 and 2 are placed on an inclined plane forming an angle α\alpha with the horizontal (Fig. 1.10). The masses of the bars are equal to m1m_{1} and m2,m_{2}, and the coefficients of friction between the inclined plane and these bars are equal to k1k_{1} and k2k_{2} respectively, with k1>k2.k_{1}>k_{2} . Find: (a) the force of interaction of the bars in the process of motion; (b) the minimum value of the angle α\alpha at which the bars start sliding down.

Reveal Answer
 (a) F=(k1k2)m1m2gcosαm1+m3; (b) tanαmin=k1m1+k2m2m1+m2\text { (a) } F=\frac{\left(k_{1}-k_{2}\right) m_{1} m_{2} g \cos \alpha}{m_{1}+m_{3}}; \text { (b) } \tan \alpha_{\min }=\frac{k_{1} m_{1}+k_{2} m_{2}}{m_{1}+m_{2}}