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Relativistic Mechanics

Problem 1.384

A neutron with kinetic energy T=2m0c2,T=2 m_{0} c^{2}, where m0m_{0} is its rest mass, strikes another, stationary, neutron. Determine: (a) the combined kinetic energy T~\widetilde{T} of both neutrons in the frame of their centre of inertia and the momentum p~\tilde{p} of each neutron in that frame; (b) the velocity of the centre of inertia of this system of particles. Instruction. Make use of the invariant E2p2c2E^{2}-p^{2} c^{2} remaining constant on transition from one inertial reference frame to another (E(E is the total energy of the system, pp is its composite momentum).

Reveal Answer
1.384. (a) T~=2m0c2(1+T/2m0c21)=777MeV\widetilde{T}=2 m_{0} c^{2}\left(\sqrt{1+T / 2 m_{0} c^{2}}-1\right)=777 \mathrm{MeV} p~=1/2m0T=940MeV/c\tilde{p}=\sqrt{1 / 2 m_{0} T}=940 \mathrm{MeV} / c (b) V=cT/(T+2m0c2)=2.12108 m/sV=c \sqrt{T /\left(T+2 m_{0} c^{2}\right)}=2.12 \cdot 10^{8} \mathrm{~m} / \mathrm{s}